IPython の %timeit で処理時間を計測してみるメモ

• Announcements — IPython

In [48]: def foo():
   ....:     arr = []
   ....:     for n in range(100):
   ....:         arr.append(n/3)
   ....:     return arr
   ....:

In [49]: %timeit foo()
10000 loops, best of 3: 22.7 us per loop

In [50]: %timeit [n/3 for n in range(100)]
100000 loops, best of 3: 12.9 us per loop