(python3.7.x)
{id:score} の入った配列 id_score_list の id:2 が score 降順で順位が何番めなのかを取得したいメモ
id_score_list = [{3: 180}, {5: 150}, {10: 150}, {1: 120}, {8: 120}, {9: 120}, {2: 110}, {7: 90}, {6: 70}, {4: 60}]
target_id = 2
ids = [list(d.items())[0][0] for d in id_score_list]
scores = [list(d.items())[0][1] for d in id_score_list]
target_index = ids.index(target_id)
print('total_count', len(scores))
print('target_id', target_id)
ranking = len(scores[:target_index]) + 1
print('ranking', ranking)
before_duplicate_ranking_count = len(set(scores[:target_index]))
print('before_duplicate_ranking_count', before_duplicate_ranking_count)
fix_ranking = before_duplicate_ranking_count + 1
print('fix_ranking', fix_ranking)
# total_count 10
# target_id 2
# ranking 7
# before_duplicate_ranking_count 3
# fix_ranking 4
id:2 のランキング7位だったが、同順位を考慮すると4位になった。
